Vsepr Theory free essay sample

According to VSEPR theory, repulsion between electron pairs in filled shells are larger than the repulsion between electron pairs in incompletely filled shells. In H2O, there are four orbitals in valence shell (one 2s and three 2p) and they are completely filled. Hence, H2O has large bond angle than H2S. electrons. Thus we can write the Lewis structure as follows. In PCl5, the P atom is surrounded by five electron pairs thus it has trigonal bipyramidal geometry. In such geometry, the central atom is present at the center of a triangle and three bonds (equatorial bonds) get directed towards the three corners of triangle, making angles of 120Â °. Remaining two bonds, one is situated above and the other is situated below the trigonal plane and are also perpendicular to plane. 10. F2O In F2O molecule, central atom is O, which is having the valence shell configuration as 2s2, 2px2, 2py1, 2pz1. We will write a custom essay sample on Vsepr Theory or any similar topic specifically for you Do Not WasteYour Time HIRE WRITER Only 13.90 / page It has two unpaired electrons and two lone pair of electrons. Thus we can write the Lewis structure as follows. In F2O, the central atom is surrounded by four electron pairs thus it has tetrahedral electrons pair geometry. However, presence of two lone pair changes its geometry to V-shape, which is its molecular geometry. It has two lone pairs which occupy larger space and push bond pairs close together thus its bond angle decreases to 103Â °. Also high electronegativity of fluorine atoms contribute in the decrease in bond angle. Fluorine atoms attract electron pairs towards itself. Thus, the electron pairs are away from central atom which decreases the repulsion between two bonds. 12. SF4 In SF4, central atom is S, which is having the valence shell configuration as 3s2, 3px1, 3py1, 3pz1, 3d1 in excited state. It is able to form four bonds because of presence of four unpaired electrons. Thus we can write the Lewis structure as follows. It is able to form six bonds because of the presence of six unpaired electrons in valence shell. Thus we can write the Lewis structure as follows. In ICl4 , central atom is iodine and its Lewis structure is- So there are four bond pairs and two lone pair thus should have octahedral geometry. But the two lone pair distorts the geometry to square planar. The bond angles are 90Â °. In SF6, the Sulphur atom is surrounded by six electron pairs thus it has octahedral geometry with bond angle 90Â °. Since there are no lone pairs its molecular geometry is also octahedral.